Seven million two hundred
ed fifty eight thousand six hundred
thirty
m5=75 degrees
m11=75 degrees
m16=65 degrees
To find 5, realize angles 5 and 8 equal 180, because they make up a straight line, line d.
180-105=75
To find 11, it is the same as finding 7. Just look at the similar sizes. Angle 7 is the same at angle 5, just turned around. There’s a term for this pair angles that I don’t remember now but it exists. Now, lines a and b are parallel, so their angles between lines that intersect both are the same too. This means, as angle 5 equals angle 7, angle 7 equals angle 11.
To find 16, we use a combination of the methods used in finding the previous angles.
180-115=65 degrees is angle 4
Angle 4=Angle 16
Knowing the two angles given and that lines a and b are parallel, you could find the measurements of every angle in each intersection if you wanted to.
Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
You start by finding two points on the line. In this case, (-4,1) and (-2,2) will do.
To get from (-4,1) to (-2,2), you need to go “up 1, right 2” which gives you a slope of m = 1/2
Next you need the b-value, which comes from the y-intercept of (0,3). The b-value is 3.
Putting the slope and b-value into y=mx+b, you have y = 1/2 x + 3.
All i got was 1 and a half months