Ask question

Ask question

All categories

2 years ago

6

Can I have help please on this math question

2 answers:

Sergeeva-Olga [200]2 years ago

8 0

I can’t see the image

GuDViN [60]2 years ago

3 0

Hi I want to help but I can’t see the image

You might be interested in

Zach Goes on holiday

olasank [31]

Answer:

total cost of the hotels is 2,296

8 0

3 years ago

What percent of 25 is 20

ipn [44]

80% bc 20/25 equals 4/5 and 4/5 equals x/100 and when you do that math it equals 80%

7 0

3 years ago

Read 2 more answers

Adventureland Amusement Park has a Ferris wheel with a diameter of 240 feet. How far would a person travel in one revolution of

UkoKoshka [18]

Answer:

3,600 ft

Step-by-step explanation:

so you would divide 240 in half and get 120 and then you would multiply 120 and 360 because the Ferris wheel is a circle and then you would divide by 12 because there is 12 inches in a foot and get your final answer 3,600 feet

3 0

3 years ago

NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE

tia_tia [17]

Answer:

Q1:

$-5\sqrt{27c^2}$

$-5\sqrt{27}\sqrt{c^2}$

$-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}$

$-5\times3\sqrt{3}\sqrt{c^2}$

$-5\times3\sqrt{3}c$

$-15\sqrt{3}c$

Q2:

$5\sqrt{72}-3\sqrt{32}$

$5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}$

$5\times6\sqrt{2}-3\times4\sqrt{2}$

$30\sqrt{2}-12\sqrt{2}$

$18\sqrt{2}$

Q3:

$\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}$

$\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}$

$6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}$

$16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}$

Q4:

$\sqrt{15n^2}\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10n^3}$

$\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}$

$\sqrt{15}\sqrt{10}n^2\sqrt{n}$

$\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{3}\sqrt{2}n^2\sqrt{n}$

$5\sqrt{6}n^2\sqrt{n}$

Q5:

$\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}$

$\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}$

Cancel off $\sqrt{x}$ :

$\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}$

Cancel off $y:$

$\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}$

Cancel off $\sqrt{y} :$

$\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}$

Multiply $\sqrt{5}$ on the numerator and denominator:

$\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}$

$\frac{\sqrt{15}\sqrt{x}}{20}$

5 0

3 years ago

3. The photo below is being enlarged to form

Umnica [9.8K]

Answer:

Not enough information

Step-by-step explanation:

Add the photo next time

4 0

2 years ago