
factorising the first denominator
x²-2x-3 = x² -3x+x-3 = (x+1)(x-3)
(a) 
finding LCD
(b) LCD of (x-3)(x+1) and (x-3) is (x-3)(x+1)
(c)

(d)



2x ! the number would be x and 2x is 2 times x!
Answer:
Step-by-step explanation:
1.
The cash flow from operating activities is = $28000.
Working Note:
Net Income $20000
Depreciation expense $3000
Increase in accounts receivable ($2000)
Increase in accounts payable $4000
Decrease in inventory $3000
Net Cash Flow from Operating Activities = 20000 + 3000 – 2000 + 4000 + 3000
Net Cash Flow from Operating Activities = $28000
2.
The cash flow from investing activities = $6000.
Working Note:
Proceeds from sale of equipment $6000
Net cash flow from investing activities = $6000
3.
The cash flow from financing activities = - $2000 or ($2000)
Working Note:
Payment of dividends ($2000)
Net Cash flow from financing activities = - $2000 or ($2000)
Answer:
5y^5
Step-by-step explanation:
there is no real solution. really i just simplified. if you wanted a real answer y would have to be giving. if not then this is all the question is asking. for you to simplify
Answer:
thats hard
Step-by-step explanation: