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Ber [7]
3 years ago
5

Which of the following is NOT a right triangle congruency?

Mathematics
1 answer:
Brums [2.3K]3 years ago
7 0
I would say the best option is A.HL
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The model shown was used to find the product of two fractions: A rectangle divided into nine columns of equal size and 4 rows of
Valentin [98]

The equation that represents the array (rectangles and area) multiplication model that sows two grey shaded columns of length one ninth each and three rows with dots of width one fourth each is option <em>a</em>

a) The equation with fractions two ninths times three fourths is equal to six thirty sixths

\dfrac{2}{9} \times \dfrac{3}{4} = \dfrac{6}{36}

<h3>What is an array (area) multiplication model?</h3>

An array representation of a multiplication is a rectangular visual order of positioning of rows and columns that indicates the terms of a multiplication equation.

Please find attached the area model to multiply the fractions

The terms of the equation represented by the model are indicated by the two columns of length one ninth each shaded grey and the three rows of width one fourth each covered with dots, such that the equation can be presented as follows;

\left(\dfrac{1}{9} +\dfrac{1}{9}\right) \times \left(\dfrac{1}{4} +\dfrac{1}{4} + \dfrac{1}{4} \right) = \dfrac{2}{9} \times \dfrac{3}{4} =\dfrac{6}{36}

The equation that the model represents is therefore;

  • The equation with fractions two ninths times three fourths is equal to six thirty sixths

Learn more about multiplication models here:

brainly.com/question/24586779

#SPJ1

8 0
1 year ago
One side of a regular pentagon measures 0.8 meters. What is the perimeter of the regular pentagon
topjm [15]
5 (the sides) x 0.8 = 4 meters
3 0
3 years ago
-) Simplify: V625<br> 15<br> 20<br> 23<br> 25
tresset_1 [31]
The answer 25 hope it helps
8 0
3 years ago
Given a triangle JLM with vertices J(-4,3), L(-2,7), and M(2,7). What would the coordinates be if it was reflected across the li
topjm [15]

Answer: M'(2, - 5), L'(-2, -5), j'(-4, - 1)

Step-by-step explanation:

When we do a reflection over a given line, the distance between all the points (measured perpendicularly to the line) does not change.

The line is y = 1.

Notice that a reflection over a line y = a (for any real value a) only changes the value of the variable y.

Let's reflect the points:

J(-4, 3)

The distance between 3 and 1 is:

D = 3 - 1 = 2.

Then the new value of y must also be at a distance 2 of the line y = 1

1 - 2 = 1

The new point is:

j'(-4, - 1)

L(-2, 7)

The distance between 7 and 1 is:

7 - 1 = 6.

The new value of y will be:

1 - 6 = -5

The new point is:

L'(-2, -5)

M(2,7)

Same as above, the new point will be:

M'(2, - 5)

3 0
3 years ago
Given A = {x ∈ ℤ : 4|x} and B = {x ∈ ℤ : 2|x}. Prove A ⊆ B.
Rashid [163]

Let a ∈ A. Then a is some integer that is divisible by 4, so we can write a = 4k for some integer k.

We can simultaneously rewrite a as a = 2•2k, so 2 clearly divides a, which means a ∈ B as well.

Therefore A ⊆ B.

4 0
2 years ago
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