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ale4655 [162]
3 years ago
6

Hey guys I have a hard time with these questions. Can someone explain it to me? :)

Mathematics
2 answers:
Alina [70]3 years ago
7 0

Answer:

Step-by-step explanation:

there are a couple ways to find slope

1. Rise over Run Method:

for this method, you use basic counting

to do this, you count the number of x spaces it takes the line to get from one y space to the next

for your line, the run is 3 because it takes 3 x spaces to get from one whole number to the next on the y spaces

you would say the rise is -1 because the line is going down, and it takes 3 x spaces to get the next pot that is on a y-axis increment

so we know the rise is -1 and the run is 3

if you put this into rise/run format, you get 1/-3

so -1/3 is you slope

2. Using the Coordinates

in this line, you see two points

the points are 1. (-1, -1), and 2. (2, -2)

using the coordinates means that you use a formula: \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

the y2 is the y value of the second coordinate (-2), the y1 is the y value of the first coordinate (-1)

the x2 is the x value of the second coordinate (2), the x1 is the x value of the  first coordinate (-1)

if you plug these it you get: -2 - (-1) / 2 - (-1)

this can be simplified to -2 + 1 / 2 + 1

and simplified again to -1/3

Qhat ever method you use, you should get the same answer. Using both methods is a good way to check your work.

frutty [35]3 years ago
6 0
The slope would be 0

This is basically how you do it if you need more help let me know

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4 0
2 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

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3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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