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3 years ago

What is the product of -5t (-t)

Mathematics

2 answers:

Paul [167]3 years ago

4 0

$-5t (-t) = 5t^2$

frutty [35]3 years ago

4 0

A negative number times a negative number equals a positive number, so...

-5t(-t) = $5t^2$

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I need help please explain how to do these two question as I did the rest of them. I just don't understand these.

Alexxandr [17]

Answer:

7. (4x +10)/(x^3 +3x^2 -16x -48)

9. -320/93

Step-by-step explanation:

7. As with adding any fractions, first you find a common denominator. When the fractions are rational expressions, it often helps to factor the denominators.

6/(x^2 -16) -2/(x^2 -x -12) = 6/((x -4)(x +4)) -2/((x -4)(x +3))

= (6(x +3) -2(x +4))/((x -4)(x +3)(x +4)) . . . . . using a common denominator

= (6x +18 -2x -8)/((x -4)(x +3)(x +4))

= (4x +10)/((x^2 -16)(x +3))

= (4x +10)/(x^3 +3x^2 -16x -48)

_____

9. First you simplify the denominator:

2/25 -5/16 = (2·16 -5·25)/(25·16) = -93/400

Then you perform the division. This can be done by multiplying by the inverse of the denominator.

(4/5)/(2/5 -5/16) = (4/5)·(-400/93) = -320/93

6 0

3 years ago

What statement makes the open sentence 12 + 3x = 30 true?MUTIPLE CHOICE QUESTION WILL MARK BRAINLIEST

Setler79 [48]

Answer:

x= 6

Step-by-step explanation:

12+3x=30

3x+12=30

3x+12-12=30-12

3x=30-12

3x=18

3x divided by 3 = 18 divided by 3

x=18 over 3

18 divided by 3 is 6

x=6

5 0

2 years ago

Read 2 more answers

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

3 years ago

One complete figure represents 100% right a percent to represent the shade portion of each figure below

forsale [732]

30% because 10 out of 10 is 100%.

So 3 out of 10 is 30%.

7 0

3 years ago

Find the percentage of vacationers from<br> question 10 who spent between $1500<br> and $2000.

mars1129 [50]

Answer:

The percentage change of vacationers is 33.3 %

Step-by-step explanation:

Given as :

The old value of the vacationers = $ 1500

The new value of the vacationers = $ 2000

Let the percentage variation = x %

Or, x % increase = $\dfrac{\tyextrm new value - \textrm old value}{\textrm old value}$ × 100

Or, x % increase = $\dfrac{\tyextrm $ 2000 - \textrm $ 1500}{\textrm $ 1500}$ × 100

Or, x % increase = $\frac{500}{1500}$ × 100

Or, x % increase = $\frac{1}{3}$ × 100

Or, x % increase = $\frac{100}{3}$

∴ x = 33.3 %

So, The percentage increase change is 33.3 %

Hence The percentage change of vacationers is 33.3 % Answer

3 0

3 years ago