Answer:
The area of the trapezoid is 57.5 square inches
Step-by-step explanation:
we know that
The trapezoid QRST can be divided into a rectangle QRDT and an isosceles right triangle RSD
see the attached figure to better understand the problem
step 1
The area of rectangle is given by the formula

we have
----> altitude

substitute

step 2
Find the area of the isosceles right triangle
The area of triangle is given by the formula

we have
---> because is an isosceles triangle
substitute

step 3
Adds the areas

Answer: Y=mx+b
B is the y intercept and the slope is M
So the answer is Y= -4x+ 0
Step-by-step explanation:
4 units right and 4 units down
The picture is super blurry so i can’t see anything
<h3>2
Answers: Choice C and choice D</h3>
y = csc(x) and y = sec(x)
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Explanation:
The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.
Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.
The same applies to...
- y = cot(x)
- y = sin(x)
- y = tan(x)
So we can rule out choices B, E and F.
Only choice C and D have graphs that do not have any x intercepts at all.
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If you're curious why csc doesn't have any roots, consider the fact that
csc(x) = 1/sin(x)
and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.
sec(x) = 1/cos(x)