What is an equation of the line that is perpendicular to y= - 4/5x +3 and passes through the point (4,12)?
1 answer:
Answer:
y = x + 7
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - x + 3 is in this form
with m = -
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
, hence
y = x + c ← is the partial equation
To find c substitute (4, 12) into the partial equation
12 = 5 + c ⇒ c = 12 - 5 = 7
y = x + 7 ← equation of perpendicular line
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It's a linear function. We need only two points to sketch the graph.
f(x) = -5x + 4 → y = -5x + 4
for x = 0 → y = -5(0) + 4 = 0 + 4 = 4 → (0, 4)
for x = 1 → y= -5(1) + 4 = -5 + 4 = -1 → (1, -1)
The domain and the range is the set of all real numbers.
