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Maksim231197 [3]
3 years ago
12

What is an equation of the line that is perpendicular to y= - 4/5x +3 and passes through the point (4,12)?

Mathematics
1 answer:
Dovator [93]3 years ago
4 0

Answer:

y = \frac{5}{4} x + 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - \frac{4}{5} x + 3 is in this form

with m = - \frac{4}{5}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{4}{5} } = \frac{5}{4}, hence

y = \frac{5}{4} x + c ← is the partial equation

To find c substitute (4, 12) into the partial equation

12 = 5 + c ⇒ c = 12 - 5 = 7

y = \frac{5}{4} x + 7 ← equation of perpendicular line

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