Construct two angle bisectors of the triangle
Answer:
Option (D) is correct
<u>Step-by-step explanation:</u>
We have to contruct two angle bisectors of the triangle.
various steps to inscribe the circle in a triangle are
- First draw a triangle
- Draw angle bisector of one angle
- Draw angle bisector of another angle
- Extent these angle bisectors, where they meet that point will be called the incenter
- From incenter draw prependicular to any side of the triangle
- The length from the point where the prependicular touches the side of triangle to the point of incenter will be radius.
- Use this radius and draw the incircle.
We have 7y = 4x + 14;
Then, y = (4/7)x + 2;
The slope of this line is 4/7;
Because another line is parallel with the first one, the chosen slope is 4/7.
Answer:
f(1)=16
Step-by-step explanation:
f(t)=-16t+32t
f(1)=-16(1)+32(1)
f(1)=-16+32
f(1)=16
Im not sure if this is right but.
Make the diameter by putting the line on points A and C. Then put the middle of the tool on point A and make the width to point C and draw a circle. Do the same for point B (other side of point A) without changing the width. Then plot the lines where the circles intersect and you have a hexagon :)
