What integer is equal to 25 3/2

Peter works at Silly's and makes $33.19 an hour. He also collects a 5.3% commission on final weekly sales. Last month, he worked

Romashka-Z-Leto [24]

Answer:

$10,318.62

Step-by-step explanation:

We have been given that works at Silly's and makes $33.19 an hour. He also collects a 5.3% commission on final weekly sales. If he works over 40 hours during any week, he earns double his hourly wage.

Peter's hourly charges during 1st and 2nd week would be $33.19 and hourly charges during 3rd and 4th week would be 2 times $33.19.

First of all, we will find total hourly income as:

$\text{Total hourly income}=\$33.19(30+40)+2\times \$33.19(49+55)$

$\text{Total hourly income}=\$33.19(70)+\$66.38(104)$

$\text{Total hourly income}=\$2323.3+\$6903.52$

$\text{Total hourly income}=\$9226.82$

Now, we will find income from commission on sales as:

$\text{Income from commission on sales}=\frac{5.3}{100}(4500+5500+3800+6800)$

$\text{Income from commission on sales}=0.053(20600)$

$\text{Income from commission on sales}=1091.8$

Peter's total earnings is the last month: $\$9226.82+\$1091.8=\$10,318.62$

Therefore, Peter's total earnings in last month was $10,318.62.

5 0

3 years ago

suppose you know that over the last 10 years, the porbabiliy that your town would have at least one ma jor stor was 40%. describ

Anuta_ua [19.1K]

Answer:

The probability of a big storm is 40%.

Now, you can find a D10 (a die with 10 faces)

You can assign 4 numbers (0, 1, 2, 3) to the event "there is a major storm"

in this way, you have 40% of having a storm.

and the other 6 numbers (4, 5, 6, 7, 8, 9) to the event "there is not a major storm". This means that we have 60% of not having a storm.

now, when you roll the dice you can see if a year there will be a storm or not.

Now, you roll the dice 5 times (for the 5 years) and take note of the results and the number of storms in those 5 rolls.

Now do the same thing a bunch of times, at least 25 times.

Now, you recorded the results in each set of rolls, now see the number of sets that have at least years with storms.

Take that number and divide it by the total number of sets of data (in this case 25, for example)

The result is the probability that we are looking for.

6 0

2 years ago

“Solve the equation. Determine if it is undefined or not.”

lozanna [386]

Answer: a) No Solution

b) Infinite Solutions (All Real Numbers)

Step-by-step explanation:

4(g + 8) = 7 + 4g

4g + 32 = 7 + 4g distributed 4 into g + 8

32 = 7 subtracted 4g from both sides

Since the statement is false because 32 ≠ 7, then there is NO SOLUTION

-4(-5h - 4) = 2(10h + 8)

20h + 16 = 20h + 16 distributed

16 = 16 subtracted 20h from both sides

Since the statement is true because 16 = 16, then there are INFINITE SOLUTIONS so x can be all real numbers.

8 0

2 years ago

Is −4[3(x−7)] and 6(14−2x) equiviant

Paraphin [41]

Answer:

Yes.

Step-by-step explanation:

Set the equations equal to each other to determine their equality.

-4[3(x - 7)] = 6(14 - 2x)

Distribute the 3 and the 6 into their respective parenthesis.

-4[3x - 21] = 84 - 12x

Distribute the -4 into the brackets.

-12x + 84

Rearrange the equations.

84 - 12x = 84 - 12x

Since the equations come out to be the same thing on both sides so that any value satisfies it, the equations are equivalent.

4 0

2 years ago

A sample of 64 observations has been selected to test whether the population mean is smaller than 15. The sample showed an avera

KengaRu [80]

Answer:

Test statistic = - 0.851063

- 2.520463

Step-by-step explanation:

H0 : μ ≥ 15

H1 : μ < 15

Sample mean, xbar = 14.5

Sample standard deviation, s = 4.7

Sample size = 64

Teat statistic :

(xbar - μ) ÷ (s/√(n))

(14.5 - 15) ÷ (4.7/√(64))

= - 0.851063

The critical value at α = 0.05

Using the T - distribution :

Degree of freedom, df = 64 - 1 = 63

Tcritical(0.05, 63) = 1.6694

Test statistic - critical value

-0.851063 - 1.6694

= - 2.520463

8 0

2 years ago