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erma4kov [3.2K]
2 years ago
14

Simplify, state all restrictions.

Mathematics
1 answer:
Kipish [7]2 years ago
7 0

The simplified expression is \frac{1 - x - y}{x + y}and the restriction is y \ne -x

<h3>How to simplify the expression?</h3>

The expression is given as:

\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

\frac{x - y}{(2x - y)(2x - 3y)} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1

Rewrite the expression as products

\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1

Cancel out the common factors

\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1

Express 4x^2 - y^2 as (2x - y)(2x + y)

\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{(2x - y)(2x + y)}{(x + y)} -1

Cancel out the common factors

\frac{1}{x + y} -1

Take the LCM

\frac{1 - x - y}{x + y}

Hence, the simplified expression is \frac{1 - x - y}{x + y}and the restriction is y \ne -x

Read more about expressions at:

brainly.com/question/723406

#SPJ1

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chubhunter [2.5K]

Answer:The center is (-5,2)

The radius is 5

Step-by-step explanation:

Equation of a circle is:

(x-h)^2+(y-k)^2=r^2

(x+5)^2+(y-2)^2=5^2

Comparing both equations we get :

The center (-5,2)

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Step-by-step explanation:

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Simplify expression X^2+x-2/x^3-x^2+2x-2
professor190 [17]

Answer:


=\frac {x+2}{x^2+2} is the simplest form of given expression.


Step-by-step explanation:

The given question is \frac{x^2+x-2}{x^3-x^2+2x-2}


To solve the problem we have to group or split middle term and then factorise


\frac{x^2+(2x-x)-2}{(x^3-x^2)+(2x-2)}


Taking x^2 common from first two terms of denominator and 2 from next two terms


= \frac{x^2+2x-x-2}{x^2(x-1)+2(x-1)}


Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms


= \frac{ x(x+2)-1(x+2)}{(x-1)(x^2+2)}



=\frac{(x+2)(x-1)}{(x-1)(x^2+2)}


Now cancel out x-1 from both numerator and denominator we get


=\frac {x+2}{x^2+2} is the required simplest form.



7 0
3 years ago
the mathematics Department of a college has 11 male professors 12 female professors 9 male teaching assistants and 12 female tea
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Make a Contingency_table

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