All of the following are typical ways through which to find an apprenticeship except:

What was the legacy Louis XIV left for his successor, Louis XV?

lidiya [134]

In the king's final hours, he received his five-year-old great-grandson, the successor future Louis XV, to share his legacy. He advised his grandson to try to avoid going to war as much as possible, and to focus on relieving the burden on the people. He said that this was the ruin of the people.

<h3>What does legacy mean?</h3>

A legacy is someone who has three mortal grandparents and one godly grandparent, or who is a further descendant of a particular deity. There is no distinction between a legacy of Ares/Mars and a legacy of Zeus/Jupiter because a legacy only counts the god it is descended from as an ancestor, not that deity's parents or grandparents. But through different ancestral combinations, it is possible to carry the genetic legacy of two or more gods.

As with Octavian's gift of prophecy or Periclymenus' descendants gaining the ability to change their shape, it is demonstrated that legacies can occasionally possess the skills of their divine ancestor. Some legacies do possess the skills of their divine ancestor, but this is only true of some of them.

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3 0

1 year ago

A humpback whale is classified as a mammal while a basking shark is a fish.

kvasek [131]

The taxonomic classification that is the same for a humpback whale and a basking shark is Phylum.

<h3>What is Taxonomic Classification?</h3>

We want to find Which taxonomy classification are the same for a humpback whale and a basking shark.

A chordate in the animal kingdom is referred to as Kingdom Animalia of the phylum Chordata. This phylum is one that includes all the vertebrates and subphyla tunicates and cephalochordates.

Chordates have peculiar characteristics such as notochord, pharyngeal slits, nerve cord, and a tail.

Therefore, we can conclude that the taxonomic classification that is the same for a humpback whale and a basking shark is Phylum.

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8 0

2 years ago

The function h(t)= -16t^2 +32t +6 can be used to model the height of a ball, in feet, t seconds after it is thrown into the air.

kotegsom [21]

Answer:22

Explanation:

4 0

3 years ago

Identify the name of the general classification in the Periodic Table for antimony and tellurium.

Annette [7]

Answer:

Group 15

Explanation:

4 0

3 years ago

Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of o

Effectus [21]

Considering the definition of empirical formula, the empirical formula is C₃H₈O₂ and the molecular formula is C₉H₂₄O₆.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, you have:

Carbon (C): 47.37 grams
Hydrogen (H): 10.59 grams
Oxygen (O): 42.04 grams

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

Carbon (C): $\frac{47.37 grams}{12 \frac{g}{mole} }$ = 3.95 moles
Hydrogen (H): $\frac{10.59 grams}{1 \frac{g}{mole} }$ = 10.59 moles
Oxygen (O): $\frac{42.04 grams}{16 \frac{g}{mole} }$ = 2.63 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Carbon (C): $\frac{3.95 moles}{2.63 moles }$ = 1.5
Hydrogen (H): $\frac{10.59 moles}{2.63 moles }$ = 4
Oxygen (O): $\frac{2.63 moles}{2.63 moles }$ = 1

Finally, since in the empirical formula the numbers of moles must be expressed in whole numbers, the ratio of atoms is multiplied by some number with which everything is obtained in simple whole numbers (in this case by 2):

Carbon (C): 1.5× 2= 3
Hydrogen (H): 4× 2= 8
Oxygen (O): 1× 2= 2

Therefore the C: H: O mole ratio is 3: 8: 2

Finally, the empirical formula is C₃H₈O₂.

<h3>Molecular formula</h3>

To obtain the molecular formula you must relate its molecular weight (PMc) with the molecular weight of the empirical formula (PMfe).

PMfe= PM (C₃H₈O₂)= 76 g/mole

The molar mass of the compound (PMc) was determined to be 228.276 g/mol. Dividing this mass PMc by the molar mass of the empirical formula PMfe gives:

228.276 g/mol ÷ 76 g/mole= 3

This means that in the molecular formula there are 3 unit formulas (empirical formulas), so it is necessary to multiply the number of all atoms by 3.

Then, the molecular formula is C₉H₂₄O₆.

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3 0

2 years ago