Considering the data in the question, the focal length of the objective lens that will give a total magnification of 200x is <u>0.8cm focal length.</u>
The whole question is:
You are using a microscope with a 10x eyepiece. What focal length of the objective lens will give a total magnification of 200x? Assume a length L = 160mm.
<h3>How was the answer derived?</h3>
Given that total magnification is 200
And the Assume length is 160
Since we used a microscope with a 10x eyepiece, the magnification would be divided by 10.
=> 200 ÷ 10 = 20.
Also, the focal length is measured in centimeters or meters; we would change the millimeters of focal length to centimeters. Therefore, we have 160 ÷ 10 = 16
The formula for the focal length of the objective lens = assumed length ÷ total magnification.
=> 16 ÷ 20 = 0.8cm.
Hence, in this case, it is concluded that the correct answer is "0.8cm."
Learn more about the focal length of the objective lens here: brainly.com/question/15744335
The volume of the base of the region enclosed by the parabola is; V = 9
<h3>Integral Volume of a Solid</h3>
The length of each cross-section is determined by the horizontal distance (parallel to the x-axis) from one end of the parabola to the other.
Thus;
y = 3 - 2x²
Making x the subject gives us;
x = ±√[(3 - y)/2]
Thus;
The horizontal distance is;
√[(3 - y)/2] - (-√[(3 - y)/2])
⇒ 2√[(3 - y)/2]
The area of each cross-section is simply the square of the section's side length, so the area would be;
A = (2√[(3 - y)/2])²
A = 6 - 2y
Thus, volume is;
V = 
Solving this gives V = 9
Read more about integral volume of solids at; brainly.com/question/14845570
According to their system of classification, the Sun is known as a yellow dwarf star. This group of stars are relatively small, containing between 80% and 100% the mass of the Sun. So the Sun is at the higher end of this group.
