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posledela
3 years ago
6

How to solve for literal equations with multiple variables

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0
<span>See examples for the method to solving literal equations for a given variable: Solve A = bh for b. Since h is multiplied times b, you must divide both sides by h in order to isolate b. Since (c+d) is divided by 2, you must first multiply both sides of the equation by 2</span>
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In About 13 days the water in the tank will hit 6000 gallons
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3 less than the quotient of 20 and x
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Answer question pls​
solmaris [256]

Answer:

B,1/5

Step-by-step explanation:

6 0
3 years ago
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A random sample of adult female reaction times has a sample mean of x¯=394.3 milliseconds and sample standard deviation of s=84.
s2008m [1.1K]

Answer:

99.7%

Step-by-step explanation:

Given that mean (μ) = 394.3 ms and standard deviation (σ) = 84.6 ms.

The empirical rule states that for a normal distribution:

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  2. 95% falls within two standard deviation (μ ± 2σ)
  3. 99.7% falls within three standard deviation (μ ± 3σ)

one standard deviation = 394.3 ± 84.6 = (309.7, 478.9). 68% falls within 309.7 and 478.9 ms

two standard deviation = 394.3 ± 2 × 84.6 = (225.1, 563.5). 95% falls within 225.1 and 563.5 ms

three standard deviation = 394.3 ± 3 × 84.6 = (140.5, 648.1). 99.7% falls within 140.5 and 648.1 ms

8 0
3 years ago
The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variab
Alex17521 [72]

Answer: 1.645

Step-by-step explanation:

Given : The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variabilities in the amount of soda in the company's 16 OZ bottles is more than the variabilities in the company's 12 OZ bottles.

Let \sigma_1^2 represents the variance for 16 OZ bottles and \sigma_2^2 represents the variance for 12 OZ bottles.

The Null and Alternative Hypothesis will be  :-

H_0:\sigma_1^2\geq\sigma_2^2

H_1:\sigma_1^2, since alternative hypothesis is left-tailed , then the test is left-tailed test.

By using the standard normal distribution table for z, the critical value for this hypothesis:-

z_{\alpha}=z_{0.05}=1.645

6 0
4 years ago
Read 2 more answers
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