Answer:
Step-by-step explanation:
<u><em>The triangles can not be proven congruent.</em></u>
We have AAA theorem ⇒ given triangles are similar for sure.
Answer:
(2,4)
Step-by-step explanation:
We have the system:
y=x+2
y=3x-2.
This is already setup for substitution.
I'm going to replace my first y with what the second y equals.
That is, I'm going to write 3x-2=x+2.
Time to solve the following for x:
3x-2=x+2
Subtract x on both sides:
2x-2= 2
Add 2 on both sides:
2x. = 4
Divide both sides by 2:
x. = 2
Now that we know x=2 and we have an equation that relates x to y: either y=x+2 or y=3x-2, doesn't matter which we use, we can find y.
So we y=x+2 with x=2 which means y=2+2=4.
So the solution, the intersection, is (2,4).
Let named variables as you said g- guinea pigs and c- chinchillas
System of equation is:
First is: c+ g = 60,005
Second is: c= 2g+5
When we replace second in first we get:
2g+5+g = 60,005 => 3g+5= 60,005 => 3g= 60,000
g=60.000/3 = 20,000 => g=20,000
When this result we replace in the second equation we get
c= 2 * 20,000 +5= 40,000+5 = 40,005
c= 40,005
Good luck!!!!
I think its a. but i could be wrong
Okay I will have an example for you. 3 and 2/7. STEP 1) multiply the denominator by the whole number. 3×7=21. STEP 2) add the numerator to 21. 21+2=23. STEP 3) 23 is the new numerator so put 23 over 7. FINAL SOLUTION 23/7.