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3 years ago

Draw the image of quadrilateral ABCD under a translation by 2 units to the right and 5 units down

Mathematics

1 answer:

slava [35]3 years ago

8 0

I don’t know if you needed a specific quadrilateral I just made a square.

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If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

2 years ago

WILL MARK BRAINLIEST!!!

Elan Coil [88]

Answer:

Step-by-step explanation:

count two up, and 5 to the right

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3 years ago

The length of a rectangle is twice its width. if the perimeter of the rectangle is 36 cm , find its area.

Brut [27]

L = Length
W = Width

L x W = area
Length = 2w

Lets find the width by solving for w.
2w + w = 36
3w = 36
3w/3 = 36 / 3
w = 12

So
L = 2 x 12 = 24
W = 12
L X W = area
24 x 12 = 288 cm^2

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3 years ago