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svlad2 [7]
3 years ago
6

A carpenter built three bookcase

Mathematics
2 answers:
Oduvanchick [21]3 years ago
6 0
What's the full and actualquestion? Describe it more please
ivolga24 [154]3 years ago
6 0
The question is incomplete u need to finish the question
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F + 25 = 50<br><br> f = <br><br> please help
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Answer:

25 because 50 minus 25 is 25

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The length of a rectangle is twice the width. The perimeter is 126 centimeters.
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a

Step-by-step explanation:

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El 2% que fraccion representa​
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2/100 or 1/50 :p la respuesta
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3 years ago
6r + 7 = 13 + 7r what is r
kumpel [21]

Answer:

6r+7=13+7r

6r+7=7r+13

6r+7−7r=7r+13−7r

−r+7=13

−r+7−7=13−7

−r=6

\frac{-r}{-1} = \frac{6}{-1}

r=−6

Step-by-step explanation:

:) This is the answer

6 0
3 years ago
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For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th
alexira [117]

Answer:

The inner function is h(x)=4x^2 + 8 and the outer function is g(x)=3x^5.

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

For the function f(x)=3(4x^2+8)^5.

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have 4x^2+8 inside parentheses. So h(x)=4x^2 + 8 is the inner function and the outer function is g(x)=3x^5.

The chain rule says:

\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

     outside function: g(x)=3x^5

     inside function: h(x)=4x^2 + 8

The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

3 0
3 years ago
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