1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sasho [114]
3 years ago
7

Factor.

Mathematics
1 answer:
neonofarm [45]3 years ago
4 0
2x(2x+5) is the answer
You might be interested in
Can someone help with this question? Thank u! :)
MatroZZZ [7]

Answer:

2.50

Step-by-step explanation:

the pattern shown in the miles driven goes up each time by 5000, stating it's going up by a constant of 5000. the cost goes up each time by 2000.

divide 5000/2000 which would give you 2.5

round it by two decimal places which gives you 2.50

7 0
3 years ago
How do you find the height of a triangle (to calculate area)?
Lilit [14]

Answer:

The height of the triangle could be found by the <u>Pythagoras theorem</u>, where the result is, with the data of the exercise:

  • <u>Height of the triangle = 10.392</u>

And the area of the triangle is:

  • <u>Area of the triangle = 31.176 units^2</u>

Step-by-step explanation:

When you have two measurements of a triangle, as the case in the picture, you can find the third with the <em>Pythagoras theorem</em>, which is:

  • <u>(opposite leg)^2 + (adjacent leg)^2 = hypotenuse^2</u>

As you can see in the picture, the measurement of the hypotenuse is 12, and the opposite leg could be 6, for this reason, we're gonna clear the adjacent leg of the formula above:

  • (opposite leg)^2 + (adjacent leg)^2 = hypotenuse^2
  • (adjacent leg)^2 = hypotenuse^2 - (opposite leg)^2

Now, we can replace the values in the formula obtained:

  • (adjacent leg)^2 = hypotenuse^2 - (opposite leg)^2
  • (adjacent leg)^2 = 12^2 - 6^2
  • (adjacent leg)^2 = 144 - 36
  • (adjacent leg)^2 = 108

Now, as we just need the adjacent leg, we take the square root of both sides:

  • adjacent leg = \sqrt{108}
  • <u>adjacent leg = 10.392 approximately</u>.

Now, with these data, we can find the area of the triangle with the next formula:

  • Area of a triangle = (base * height) / 2
  • And we replace the measurements:
  • Area of a triangle = (6 * 10.392) / 2
  • <u>Area of a triangle = 31.176</u>

As the image does not contain units, it would be simply this number, however, <em>you should know that the area units are usually given squared, for example: in^2 or ft^2</em>.

4 0
3 years ago
Which of the following statements is true ? HELLLLP ASSSSAPP TRYAN GRADUATE UKKK
Soloha48 [4]

Answer:

Both are irrational

Step-by-step explanation:

\sqrt{\frac{4}{9} } is a trick as it does simplify to \frac{2}{3} , but that is irrational

4 0
3 years ago
The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
Andrews [41]
<span>The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
have four terms and 1 constant
</span>
5 0
4 years ago
What data does the x-axis show?<br> 25 points ***!!
Aleonysh [2.5K]

Answer:

time in weeks

Step-by-step explanation:

6 0
3 years ago
Other questions:
  • What is the value of the expression, written in standard form?
    6·2 answers
  • Use factoring to solve for all solutions of the quadratic equation.
    15·1 answer
  • Stephanie has $152 in the bank. She withdraws $20. Then she deposits $84. Write an addition expression to represent this situati
    12·1 answer
  • In diagram below De is parallel to XY what is the value of X
    8·2 answers
  • Let x be a continuous random variable that is normally distributed with a mean of 25 and a standard deviation of 6. Find the pro
    11·1 answer
  • 5 for every $2.50 10 for every ?​
    7·1 answer
  • What are the factors of x^2-8x-20
    10·1 answer
  • Math pls pls help help no trolls i really need this grade​
    6·1 answer
  • What is the value of the function at x=−2?
    10·1 answer
  • WILL GIVE BRAINIEST PLEASE ONLY ANSWER WITH AN ANSWER
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!