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3 years ago

Can someone fill this out? I am very busy today and I need someone to fill this out.

Mathematics

2 answers:

saveliy_v [14]3 years ago

7 0

Definitely a carrot

AysviL [449]3 years ago

6 0

Answer:

Uh i think its a uhhh carrot

Step-by-step explanation:

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#9. Write the measurement as shown below

Scilla [17]

There are 16 lines between 1 and 2, so each line would be 1/16. The arrow is pointing to the 3rd line so it would be 3/16

4 0

3 years ago

Find the slope of the line that contains the following pair of points (1,6) (9,-4)

motikmotik

Answer:

The slope is -5/4 or -1.25

Step-by-step explanation:

m= (y2-y1)/(x2-x1)

m= (-4-6)/(9-1)

m=(-10)/8

m= -5/4

3 0

3 years ago

Read 2 more answers

Describe the set of all complex numbers that are at a distance of 2 units from the origin.

Andreyy89

Answer:

The description of the set is $A = \{s\in \mathbb{C}|\|s\| = 2\}$ .

Step-by-step explanation:

From Complex Analysis, we remember that complex numbers are numbers whose form is:

$s = a+i\, b$ , $a,b \in \mathbb{R}$ (1)

Where $i = \sqrt{-1}$ .

In addition, the distance from the origin is defined by the following Pythagorean identity:

$\|s\| = \sqrt{a^{2}+b^{2}}$ (2)

The following condition must be satisfied:

$\|s\| = 2$

Then, the set of all complex numbers that are at a distance of 2 units from the origin is described below:

$A = \{s\in \mathbb{C}|\|s\| = 2\}$ (3)

8 0

3 years ago

What is the area of the hexagon?

Dominik [7]

Answer:

68 square meters

Step-by-step explanation:

The hexagon is made up of two trapezoids. Use the formula to find the area of each trapezoid then add those two areas together.

Area of a trapezoid (add the two bases together, multiply by the height then divide by 2):

$A = \frac{1}{2} (b_{1}+b_{2})h$

Top trapezoid:

$A = \frac{1}{2} (5 + 12)4\\A = \frac{1}{2} (17)4\\A= \frac{1}{2} (68)\\A = 34$

Bottom trapezoid (identical to the top trapezoid):

$A = \frac{1}{2} (5 + 12)4\\A = \frac{1}{2} (17)4\\A= \frac{1}{2} (68)\\A = 34$

Add the areas together:

34 + 34 = 68

4 0

2 years ago

Trigonometry pile up. Anyone mind helping me out with this one?

S_A_V [24]

$cos34^o=\frac{8}{a};\ cos34^o\approx0.829\\\\\frac{8}{a}=0.829\to a\approx9.65\\\\9.65-2.5+3.6=10.75\\\\cos11^o=\frac{b}{10.75};\ cos11^o\approx0.981\\\\\frac{b}{10.75}=0.981\to b\approx10.55\\\\10.55-2.1+2.9=11.35\\\\c^2+3.8^2=11.35^2\\\\c^2=11.35^2-3.8^2\\\\c\approx10.69$

$10.69-3.2=7.49\\\\tan42^o=\frac{d}{7.49};\ tan42^o\approx0.9\\\\\frac{d}{7.49}=0.9\to d\approx6.74\\\\sin37^o=\frac{6.74}{e};\ sin37^o\approx0.602\\\\\frac{6.74}{e}=0.602\to e\approx11.2\\\\11.2+4.3=15.5\\\\sin53^o=\frac{f}{15.5};\ sin53^o\approx0.8\\\\\frac{f}{15.5}=0.8\to f\approx12.4$

$12.4-2.2=10.2\\\\g^2=10.2^2+1.7^2\to g\approx10.34\\\\cos21^o=\frac{10.34}{h};\ cos21^o\approx0.934\\\\\frac{10.34}{h}=0.934\to h=11.07\\\\11.07+1.7=12.77\\\\sin71^o=\frac{x}{12.77};\ sin71^o\approx0.946\\\\\frac{x}{12.77}=0.946\to x\approx12.1\ (cm)\leftarrow Answer$

4 0

3 years ago