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VladimirAG [237]
3 years ago
5

A cone has a radius of 8 inches and a height of 12 inches.What is the exact volume of the cone?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
8 0
The\ volume\ of\ the\ cone:V=\frac{1}{3}\pi r^2H\\\\where\\r-radius\\H-height\\----------------\\\\r=8\ in\ and\ H=12\ in\\\\therefore\\\\V=\frac{1}3{\pi\cdot8^2\cdot12=\frac{1}{\not3_1}\cdot\frac{\not12^4}{1}\cdot64\pi=4\cdot64\pi=\boxed{256\pi\ (in^3)}
In-s [12.5K]3 years ago
3 0

Volume = 256\pi in ^{3}

Work is attached in the image provided.

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For starters,

tan(2θ) = sin(2θ) / cos(2θ)

and we can expand the sine and cosine using the double angle formulas,

sin(2θ) = 2 sin(θ) cos(θ)

cos(2θ) = 1 - 2sin^2(θ)

To find sin(2θ), use the Pythagorean identity to compute cos(θ). With θ between 0 and π/2, we know cos(θ) > 0, so

cos^2(θ) + sin^2(θ) = 1

==>  cos(θ) = √(1 - sin^2(θ)) = 4/5

We already know sin(θ), so we can plug everything in:

sin(2θ) = 2 * 3/5 * 4/5 = 24/25

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==>  tan(2θ) = (24/25) / (7/25) = 24/7

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