O que posso acrescentar é que 3 linhas de segmentos reflexivas no triângulo definem o baricentro... estas 3 linhas serão as medianas do triângulo e o baricentro divide as linhas em 3 partes iguais.
Answer: 81%
Step-by-step explanation:
From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,
84% and 83% in 5 tests and the student wants to maintain an average of 80%.
The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:
First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:
= 80 × 6
= 480
We then add all the 5 test scores. This will be:
= 71 + 89 + 72 + 84 + 83
= 399
We then subtract the values gotten. This will be:
= 480 - 399
= 81
This means the student must get at least 81%
Assuming that you're talking about a standard deck of 52 cards, there are 4 tens and 4 aces.
So, at the beginning, you have probability 4/52=1/13 to draw a ten.
You replace, and you have an identical probability to draw an ace (you still have 4 favourable cases over 52 total cases).
Multiply the two probabilities to find the answer:
Answer:
The correct system would be B
Step-by-step explanation:
The reason that it is B, is that we would first need an equation for the total number of baskets he made. In this one, we need the two pointers added to the three pointers to get the total of 65
w + t = 65
The second equation needs to be the total number of points (151). That should be equal to the value of the shot times the amount of them made.
2w + 3t = 151
This is option B, and is therefore the answer.
Exact Form: 21√6
Decimal Form: 51.43928459
Hope this helps! :)