A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
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Answer:
V lies in the exterior of <STU.
Step-by-step explanation:
V lies in the exterior of <STU.
Answer: <em>Line of reflection is y = 2 x + 2</em>
Step-by-step explanation: <em> I Hope this helps</em>
Answer:
You would have 1/6 of your money remaining.
Step-by-step explanation:
Let's write an equation for this.
1 - (2/3 + 1/6)
First, let's multiply the numerator and denominator of 2/3. You get 4/6!
1 - (2/3 + 1/6)
1 - (4/6 + 1/6)
Next, let's add 4/6 and 1/6. You get 5/6!
1 - (4/6 + 1/6)
1 - 5/6
Finally, let's turn 1 into 6/6 and do 6/6 - 5/6!
1 - 5/6
6/6 - 5/6
1/6
You would have 1/6 of your money remaining.
The answer is C. 6 times 4 is 24 and 1/4 times 4 is 1. therefore 24 + 1 = 25
