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skelet666 [1.2K]
3 years ago
11

The radius of a circle is 6 meters. What is the area of a sector bounded by a 45° arc?

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

the sector bounded by 45 degrees arc is 70.56

Step-by-step explanation:

Just did it

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Plz help! What is the surface area of the figure?​
dexar [7]

Answer:

483 ft²

Step-by-step explanation:

2(7x7)=   98

3(5x12)=180

2(12x5)=120

2(5x5)=   50  

1(7x5) =  <u> 35   </u>

              483

               

6 0
3 years ago
an electrician charges a fee of $50 plus $35 per hour. let y be the cost in dollars of using the electrician for x hours. write
Alex Ar [27]

Answer:

y = 50 + 35x we dont know how many hours they worked

Step-by-step explanation:

7 0
2 years ago
Jennifer began an exercise program in which she ran 4 blocks the first day and then two blocks more than the previous day for ea
Andrews [41]

Answer:

84 blocks.

Step-by-step explanation:

If you are adding 2 to each day (which already has 4) in a 2 week period (14 days) than you would have to time 2(14) and 4(14) and add them. Thus would make the answer 84 blocks.

5 0
2 years ago
Which inverse operation should be performed first?: m = 7 = 32.
Mumz [18]
The answer is multiplication
7 0
2 years ago
A rectangle has a length that is 2 meters more than the width. The area of the rectangle is 288 square meters. Find the dimensio
Rufina [12.5K]

Answer:

L = 18 and w = 16

Step-by-step explanation:

The area of a rectangle is found by A = l*w. Since the length here is 2 more than the width or 2 + w and the width is w, substitute these values and A = 288 to solve for w.

A = l*w\\288 = w(2+w)\\288 = w^2 + 2w

To solve for w, move 288 to the other side by subtraction. Then factor and solve.

w^2 + 2w  - 288 = 0 \\(w +18)(w-16) = 0\\

Set each factor equal to 0 and solve.

w - 16 = 0 so w = 16

w + 18 = 0 so w = -18

Since w is a side length and length/distance cannot be negative, then w = 16 is the width of the rectangle.

This means the length is 16 + 2 = 18.

7 0
2 years ago
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