Question

Simplify

Answer 1

$Given : \frac{\frac{x + 2}{x^2 - 6x - 16}}{\frac{1}{9x}}$

$\implies \frac{9x(x+ 2)}{x^2 - 6x - 16}$

$\implies \frac{9x(x + 2)}{x^2 - 8x + 2x - 16}$

$\implies \frac{9x(x + 2)}{x(x - 8) + 2(x - 8)}$

$\implies \frac{9x(x + 2)}{(x - 8)(x + 2)}$

$\implies \frac{9x}{(x - 8)}$