Set the whole expression = to 0 and solve for x.
3x^(5/3) - 4x^(7/3) = 0. Factor out x^(5/3): x^(5/3) [3 - 4x^(2/3)] = 0
Then either x^(5/3) = 0, or 3 - 4x^(2/3) = 0.
In the latter case, 4x^(2/3) = 3.
To solve this: mult. both sides by x^(-2/3). Then we have
4x^(2/3)x^(-2/3) = 3x^(-2/3), or 4 = 3x^(-2/3). It'd be easier to work with this if we rewrote it as
4 3
--- = --------------------
1 x^(+2/3)
Then
4
--- = x^(-2/3). Then, x^(2/3) = (3/4), and x = (3/4)^(3/2). According to my 3 calculator, that comes out to x = 0.65 (approx.)
Check this result! subst. 0.65 for x in the given equation. Is the equation then true?
My method here was a bit roundabout, and longer than it should have been. Can you think of a more elegant (and shorter) solution?
Hello,
If 1 black shoe is selected from a bin of 6 black shoes and 4 brown shoes and not replaced, then there are 5 black shoes and 4 brown shoes remaining. To find the probability that the a black shoe will be selected out of 5 black shoes and 4 brown shoes, we divide the number of black shoes over the total number of shoes (Each selection of a shoe is independent).
Doing this, we get 5 / (5+4) = 5/9 ≈ 0.55
The probability that a second shoe selected will be black is 0.55.
Hope this helps!
Answer:
yes, brother can go
Step-by-step explanation:
Apparently, you're not to think to deeply about this function. Rather, you are to take the question at face value. It is asking if the value of T(3) is more than 58.
Evaluation of polynomials is facilitated by writing them in "Horner form."
T(x) = ((x -2)x +1)x^2 +27
T(3) = ((3 -2)3 +1)9 +27 = (3 +1)9 +27 = 36 +27
T(3) = 63
The coldest temperature is supposed to be 63 degrees, which is above 58 degrees. Baby brother can come along.
Y=x+3.1
Y=-2x+4.5 you can use Desmos to check
The answer is A I hope this helps
