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2 years ago

Write an equation of the line passing through the given points. (3,-25) and (-3,5) y=

Mathematics

2 answers:

horrorfan [7]2 years ago

7 0

Answer:

the answer to the problem is y= -5x - 10

MaRussiya [10]2 years ago

5 0

Answer:

y = -5x -10

Step-by-step explanation:

This is the slope-intercept form:

$y-y_{1} = m(x -x_{1})$

First, we look for the slope. The slope is found by using the equation:

$m = \frac{y_{2}-y_{1} }{x_{2} -x_{1}}$

$m = \frac{5 - (-25)}{-3 - 3} = \frac{30}{-6} = -5$

m = -5.

Now, given the two points, our y₁ is -25, and our x₁ is 3. Therefore, we substitute these values into the equation, and get:

y - (-25) = -5(x - 3)

y + 25 = -5(x - 3)

y + 25 = -5x + 15

y = -5x + 15 -25

y = -5x -10

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Janice works a babysitting job and makes $30 dollars a night. She babysits approximately 3 nights a week. What is her annual inc

34kurt

Answer:

her annual income is $360

Step-by-step explanation:

$360

4 0

2 years ago

Please help. Write as a single logarithm, a) log(13)+log(4) b) log(small 5)(14)-log(small 5)(2)

dsp73

Answer:

a) $\log 52$

b) $\log_57$

Step-by-step explanation:

Use logarithm properties:

$\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}$

Then

a) $\log 13+\log 4=\log 13\cdot 4=\log 52$

b) $\log_514-\log _52=\log _5\dfrac{14}{2}=\log _57$

7 0

3 years ago

Use the following scenario to answer the question below:

Aleks [24]

Answer:

9 hr * 60 min/hr = 540 min. 540 min * 60 sec/min = 32,400 sec. Use the method described by panic mode: round the number down until there is only one non-zero digit left. Here, 32,400 rounds down to 30,000. Now count the number of zeroes; the result is the order of magnitude: 4. (You see this in scientific notation also: 30,000 = 3 × 10^4.)

5 0

1 year ago

Mr. Martin’s math test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Let x be

klio [65]

(x + y = 29)
(y = 29 - x)
(5x + 2(29 - x) = 100)
(5x + 58 - 2x = 100)
(3x = 42)
(x = 14)
(y = 15)
(14 5-point questions and 15 2-point questions)

6 0

2 years ago

Read 2 more answers

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

2 years ago