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3 years ago

20pts BRAINLIEST Please help? Data containing two variables is called ___________ ?

Mathematics

2 answers:

MissTica3 years ago

6 0

Bivariate data contains two variables

xeze [42]3 years ago

4 0

Bivariate data is the answer

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Please solve!! solve for y 3x-y=16 Will name the Brainliest!!

algol [13]

Answer:

y= 5.333

Step-by-step explanation:

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3 years ago

A physician orders a dosage of 85mg. The drug on hand is labeled “0.1g in 1.5mL”. How many ML should the pharmacy technician giv

marin [14]

Answer:

Step-by-step explanation:

0.1 g = 100 mg

85 mg / 100 mg = x mL / 1.5 mL

x = 1.275 mL

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2 years ago

Write 0.000012001 in scientific notation. 0.000012001 =

LUCKY_DIMON [66]

Answer:

The answer is 1.2001 * 10^-5

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3 years ago

Find the percent of increase. Original number: 45 books New number: 63 books

BARSIC [14]

Answer:

Step-by-step explanation:

first you multiply 45 by .40 you multiply by .40 because that is the percent increase.

45*.40=18

then you just add the 18 to 45 which get you 63.

answer:40%

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3 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago