Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
The answer to the question
Answer:
The answer is A.
Step-by-step explanation:
Hope this helped! :)
Answer:

Step-by-step explanation:
we know that
In a parallelogram the diagonals bisect each other
The figure XYZW is a parallelogram
so
VW=VY
VX=VZ
<em>Find the value of b</em>
VW=VY
substitute the given values

solve for b

Find the length of YW
----> by addition segment postulate

substitute the value of b
