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Leona [35]
3 years ago
5

The surface area of a cone with radius r units and slant height s units is shown below:

Mathematics
2 answers:
Ganezh [65]3 years ago
4 0
Surface area of a cone = π{rs+r²}<br />                                     =πr{s+r}<br />part 1:if π is 6 units and s is 4 units then r would be 3.14 ×6 {4+6}<br /><br />part 2: area of a cone = 3.14 ×6×10<br />                                  =31.4×6<br />                                    = 188.4 units²<br />the surface area = 188.4 <br />units²<br /> hope i helped 
Oliga [24]3 years ago
3 0
S.A=π(rs+r^{2} )
Substituting for values of x;
S.A=3.14(6*4+6^{2})
S.A=188.4 units
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System of conics help
ZanzabumX [31]

Answer:

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Step-by-step explanation:

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substituting for (x-2)^{2} in the second equation given we get

\frac{16-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} = 1

\frac{-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} =0

∴ y=3

Putting y=3 in the first equation we get

(x-2)^{2} = 16

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7 0
3 years ago
Factor 7x3y4−7x2y5 completely.
Anastasy [175]

Answer:

B

Step-by-step explanation:

when we factor completely, we take a look at what is the biggest common factor of 7x³y⁴ and 7x²y⁵. In this case it is 7x²y⁴.

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7 0
3 years ago
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solniwko [45]

Answer:

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

Step-by-step explanation:

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<u>step 2:-</u>

solving on both sides

1-x=A(x^{2} +1)+(Bx+C)x......(2)

substitute x =0 value in equation (2)

1=A(1)+0

<u>A=1</u>

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

<u>-</u>1  =  C

<u>step 3:-</u>

substitute A,B,C values in equation (1)

now  

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by using integration formulas

i)  by using \int\limits \frac{1}{x}   d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\.....(b)

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<u>step 4:-</u>

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we get answer is

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

6 0
3 years ago
You take a quiz with 6 multiple choice questions. After you studied your estimated that you would have about an 80 % chance of g
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Answer:

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p is the probability of each individual event

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therefore, for this questions we have:

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4 0
3 years ago
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Ugo [173]
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5 0
3 years ago
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