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DerKrebs [107]
4 years ago
10

Help me plzzzz its due tmmr

Mathematics
1 answer:
Fittoniya [83]4 years ago
8 0
I'm pretty sure the answers are
9-m
7-n
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What would be a model that could be used to describe this situation?
Taya2010 [7]
I confused ! I don't get what your trying to say please explain better !
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Dwight has nine coins consisting of only pennies and nickels. If the total value of the coins is 29 cents, how many nickels does
iragen [17]

Answer:

5 nickels

Step-by-step explanation:

guess and check

5 nickles and 4 pennies=9coins=29 cents

4 0
3 years ago
∠A=24∘and ∠B=24∘ What term can be used to describe these two angles?
NeTakaya
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3 years ago
Read 2 more answers
−2y 3 +3y−3y+7y 3 +1+2−5
Xelga [282]

Answer:

15y-2

Step-by-step explanation:

Please use parentheses if needed, this has me confused but without them, I solved it.

(-2y)(3)+3y-3y+7y(3)+1+2+5

-6y+3y+-3y+21y+1+2+-5

Combine like terms

(-6y+3y+-3+21y) + (1+2+-5)

15y + -2

Answer again: 15y - 2.

8 0
3 years ago
Draw the graph for f(x)=x-1/x^2-x-6 and state:a. the x-intercept(s).b. the y-intercept.c. the equation(s) of any vertical asympt
Zigmanuir [339]

ANSWER:

a. (1, 0)

b. (0, 1/6)

c. x = -2. x = 3

d. y = 0

e. The asymptotes have the form of a line and divide the function into 3 parts.

f.

\begin{equation*} \text{Domain: }\left(-\infty\:,\:-2\right)\cup\left(-2,\:3\right)\cup\left(3,\:\infty\:\right) \end{equation*}

g.

\text{Range}(-\infty,\infty)

STEP-BY-STEP EXPLANATION:

We have the following function:

f\left(x\right)=\frac{x-1}{x^2-x-6}

The graph corresponding to the function is the following:

We determine in each case what the statement asks for, like this:

a. the x-intercept(s):

\begin{gathered} \text{ in this case y = 0, therefore:} \\  \\ \frac{x-1}{x^2-x-6}=0 \\  \\ x-1=0\cdot(x^2-x-6) \\  \\ x=1 \\  \\ \text{The x-intercept is \lparen1, 0\rparen} \end{gathered}

b. the y-intercept:

\begin{gathered} \text{ in this case x = 0, therefore } \\  \\ y=\frac{0-1}{0^2-0-6} \\  \\ y=\frac{-1}{-6} \\  \\ y=\frac{1}{6} \\  \\ \text{ The y-intercept is }\:\left(0,\frac{1}{6}\right) \end{gathered}

c. the equation(s) of any vertical asymptote(s). The horizontal asymptotes are the values that x cannot take since the function would be discontinuous for those values.

In this case, since it is a rational function, it would be when the denominator is 0, therefore, we solve the following:

\begin{gathered} x^2-x-6=0 \\  \\ (x-3)(x+2)=0 \\  \\ x-3=0\rightarrow x=3 \\  \\ x+2=0\operatorname{\rightarrow}x=-2 \\  \\ \text{ The equation\lparen s\rparen of any vertical asymptote are:} \\  \\ x=3,x=-2 \end{gathered}

d. the equation of the horizontal asymptote. If the degree of the denominator is greater than that of the numerator, the horizontal asymptote is the x-axis, that is:

y=0

e. information about the behavior at the asymptote(s).

In this case the behavior of the asymptotes are straight lines that represent values that the function cannot take or cannot reach, divide the function into 3 parts.

f and g.

In this case, the domain is the interval of values that x can take and the range is the interval of values that y can take.

Therefore:

\begin{gathered} \text{Domain: }\left(-\infty\:,\:-2\right)\cup\left(-2,\:3\right)\cup\left(3,\:\infty\:\right) \\  \\ \text{Range:}\:\left(-\infty\:,\:\infty\:\right) \end{gathered}

8 0
1 year ago
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