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kolezko [41]
2 years ago
14

A hot vanilla latte recipe calls for 2 1/2 cups of almond milk and makes 10 servings. How many cups of milk are needed for 15 se

rvings?
Mathematics
2 answers:
tatyana61 [14]2 years ago
6 0

Answer:

3.75

Step-by-step explanation:

1.25+2.5= 3.75

if ya need more help just ask

Finger [1]2 years ago
4 0

3 is needed for it had 1 to 1/2 u get a whole meaning it would go up so for 15 serving u would 3 whole cups of milk np

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If you factor y^2-81 COMPLETELY, would it just be (y-9)(y+9), or would it be something like y(3)(-3)y(3)(3)?
Vladimir79 [104]
That would be (y - 9)(y +9). When two binomials are multiplied, the distributive property is applied. However, if the equation is <span>y(3)(-3)y(3)(3), you just simply multiply them altogether. That would be -81y^2, which is not equivalent with y^2 - 81.</span>
4 0
3 years ago
A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week
Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals​ surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                              P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of individuals who work at home at least once per week = \frac{41}{250} = 0.164

           n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                             level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<em>99% confidence interval for p</em> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

= [ 0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } , 0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } ]

 = [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0
2 years ago
Please help me on this. you need to match the terms to the correct number.
Gnom [1K]

Answer:

64=8

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9=3

20=4.5

4=2

1=1

67=8.2

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5 0
3 years ago
Jake heard that spinning—rather than flipping—a penny raises the probability above 50\%50%50, percent that the penny lands showi
mamaluj [8]

Answer:

3.60

Step-by-step explanation:

Kahn Academy

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2 years ago
PLEASE HELP!!! BRAINLIESt!! THANK YOUU
vredina [299]

Answer:

ok

Step-by-step explanation:

7 0
3 years ago
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