Vertex is now at (-1,5)
for
y=a(x-h)^2+k
vertex is (h,k)
so veertex is (-1,5)
y=a(x-(-1))^2+5
y=a(x+1)^2+5
a is a constant, we will asssume that it is 1 because all the choices have 1
y=1(x+1)^2+5
y=(x+1)^2+5
2nd option
Answer:
![f(x) =\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
Hello!
Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:
![g(x) = \sqrt[3]{x-5}+7](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx-5%7D%2B7)
To have the the parent function, we must find the parent one, let's call it by f(x).
![f(x) =\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%5Csqrt%5B3%5D%7Bx%7D)
This function satisfies the Domain of the given one, because the Domain is still
and the range as well.
Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.
Answer:
360
Step-by-step explanation:
The equation 13x+30=134 can be used to find the number of months Kenneth can receive internet service.
Step-by-step explanation:
Given,
Start up fee to receive internet = $30
Per month charges = $13
Total amount = $134
Let,
x be the number of months.
y be the total cost.
y = 13x+30
Putting y=134

The equation 13x+30=134 can be used to find the number of months Kenneth can receive internet service.
Keywords: equation, addition
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Based on the populations of the town from 2000 to 2008, the average rate of change of the population between 2002 and 2004 is -6.1%
The average rate of change between 2002 and 2006 is -4.88%
<h3>What is the average rate of change?</h3>
The average rate of change can be found as:
=Change in population / Population in base year
The average rate of change in population between 2002 and 2004 is:
= (77 - 82) / 82
= -6.1%
The average rate of change in population between 2002 and 2006 is:
= (78 - 82) / 82
= -4.88%
Find out more on the average rate of change at brainly.com/question/23434598
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