In circle p, td¯¯¯¯¯ and tb¯¯¯¯¯ intersect at t. ta=10, tc=8, cd=12, and ab=x+2. find ab. circle p. answer
1 answer:
The answer is AB = 6.
External value x (external value + internal value) =
External value x (external value + internal value) of the other side
Substitute, transpose, and simplify.
TA x (TA + AB) = TC x (TC + CD)
10 x (10 + (x + 2)) = 8 x (8 + 12)
120 + 10x = 160
10x = 40
x = 4
To find AB: x + 12; x = 4
AB = x + 2
AB = 4 + 2
AB = 6
External value x (external value + internal value) =
External value x (external value + internal value) of the other side
Substitute, transpose, and simplify.
TA x (TA + AB) = TC x (TC + CD)
10 x (10 + (x + 2)) = 8 x (8 + 12)
120 + 10x = 160
10x = 40
x = 4
To find AB: x + 12; x = 4
AB = x + 2
AB = 4 + 2
AB = 6
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By how much the product of and
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Solution:
First we need to find the product of and
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Now subtract 5 from the product.
Therefore, the product of and
is 9.85 greater than 5.
Answer:
(g-f) (-1)= sqrt(15)
(f/g)(-1)= 0
(g+f)(2)=sqrt(3)-3
(g*f)(2)=-3*sqrt(3)
Step-by-step explanation:
We have to eval the expressions given in the point indicated.
Lets start by the first equation
(g-f)(-1)= g(-1) - f(-1)= =
Now, lest continue with the others
(f/g)(-1)= f(-1)/g(-1)= (1-1)/sqrt(15)=0
(g+f)(2)=g(2)+f(2)=sqrt(3)-3
(g*f)(2)=g(2)*f(2)=sqrt(3)*(-3)=-3sqrt(3)