In circle p, td¯¯¯¯¯ and tb¯¯¯¯¯ intersect at t. ta=10, tc=8, cd=12, and ab=x+2. find ab. circle p. answer
1 answer:
The answer is AB = 6.
External value x (external value + internal value) =
External value x (external value + internal value) of the other side
Substitute, transpose, and simplify.
TA x (TA + AB) = TC x (TC + CD)
10 x (10 + (x + 2)) = 8 x (8 + 12)
120 + 10x = 160
10x = 40
x = 4
To find AB: x + 12; x = 4
AB = x + 2
AB = 4 + 2
AB = 6
External value x (external value + internal value) =
External value x (external value + internal value) of the other side
Substitute, transpose, and simplify.
TA x (TA + AB) = TC x (TC + CD)
10 x (10 + (x + 2)) = 8 x (8 + 12)
120 + 10x = 160
10x = 40
x = 4
To find AB: x + 12; x = 4
AB = x + 2
AB = 4 + 2
AB = 6
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Answer:
Step-by-step explanation:
To solve this we should use the Euclidean division :
- Our polynomial function is 16-2x³-6x²+x+9=-2x³-6x²+x+9
- we should divided by : 4+3x-2=3x+2 and see the rest
Here is a picture with the operation
- the rest is 47/9 so the number I SHOULD SUBSTACT IS 47/9
