PLEASE HELP MY SIS IS BREAKING DOWN CRYING
1 answer:
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Answer:
Step-by-step explanation:
By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: , or equivalently,
.
Given our linear equation 3x + y = 3 (or y = -3x + 3):
We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is .
To test whether this is correct, we can take first slope, , and multiply it with the negative reciprocal slope
:
Therefore, we came up with the correct slope for the other line, which is .
Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:
Answer:
Step-by-step explanation:
<u>Roots of a polynomial</u>
If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula
Where a is an arbitrary constant.
We know three of the roots of the degree-5 polynomial are:
We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:
Let's build up the polynomial, assuming a=1:
Since:
Operating the last two factors:
Operating, we have the required polynomial: