Answer:
-5.4c
Step-by-step explanation:
We're combining two "like" terms here.
It may make the problem easier to visualize if we write one of these terms over the other, as follows:
-2.6c
- 2.8c
----------
Adding, we get:
-2.6c
- 2.8c
----------
- 5.4c (answer)
That would be the area of a circle of radius 12 miles
= pi r^2 = 452.4 square miles to nearest tenth.
Answer:

Step-by-step explanation:


Therefore ,

|a| = -a if a < 0
The absolute value and the opposite of rational number is equal when a number is negative.
Examples:
|-7| = - (-7) = 7
|-0.5| = - (-0.5) = 0.5
Answer:
12
Step-by-step explanation:
Using the pythagorean theorem, we know that a^2+ b^2=c^2
In our case, we know b, which is 5 and c which is 13.
If we plug that into the equation, we get a^2+ 5^2 = 13^2
Next, we simplify the equation. a^2 + 25 = 169
Then we subtract 25 from 169. 169 - 25 = 144.
Lastly, we do the square root of 144 and we get 12 which is the missing side.