Question

Will give brainliest!

Answer 1

Check the picture below, it hits the ground when y = 0.

$\bf ~~~~~~\textit{initial velocity}\\\\ \begin{array}{llll} ~~~~~~\textit{in feet}\\\\ h(t) = -16t^2+v_ot+h_o \\\\ \end{array} \quad \begin{cases} v_o=\stackrel{0}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{162}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\\\ h(t)=-16t^2+0t+162\implies 0=-16t^2+162\implies 16t^2=162 \\\\\\ t=\cfrac{162}{16}\implies t=\cfrac{81}{8}\implies t=10\frac{1}{8}$