I believe that the answer is D, A checking account. The rest of the answers are silly.
First of all we have to find the slope
m = y₂-y₁ / x₂-x₁
m = -8 + 16 / -10 + 8
m = 8/-2
m = -4
y-y₁ = m (x-x₁)
y + 8 = -4 (x + 10)
y + 8 = -4x - 40
y = -4x -40 - 8
y = -4x -48
Answer:
THE ANSWER is ur mom
Step-by-step explanation:
lol im REPORTING YOU :)
<h3>
Explanation:</h3>
Class boundaries need to be defined so that a point on the boundary is unambiguously placed in one class or the other. With these boundaries, a value of 120 might be placed in the first or the second class—<em>we don't know which</em>.
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It is customary to define class boundaries between data values 60.5–120.5, for example, so that no data value can fall on the boundary, or as a semi-open interval [60, 120), so that a boundary value is clearly placed into a specific class.
Answer:
Step-by-step explanation: