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3 years ago

5.Solve the system using substitution.

1 answer:

8 0

OK first convert one of the equations into Y=MX+b form

Y-2x = 3
Add 2X

Y = 2x +3
Now substitute this equation in the other one.
So it would be

3X - 2Y = 5

3X-2(2x+3) = 5

Now solve for y

3X - 4X - 6 = 5

-1X - 6 = 5

Add 6

-1X = 11

X = -11

Now substitute this into one of the equations

Y - 2X = 3

Y -2(-11) = 3

Y +22 = 3

y = 3-22

y = -19

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3 years ago

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3 years ago

based on the simulation, what is the probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to

Triss [41]

Using the binomial distribution, supposing that 0.3 of the callers have to wait more than 8 minutes to have their calls answered, it is found that there is a 0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

For each caller, there are only two possible outcomes, either they have to wait more than 8 minutes to have their calls answered, or they do not. The probability of a caller having to wait more than 8 minutes is independent of any other caller, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

10 callers, hence $n = 10$
Suppose that 0.3 of them have to wait more than 8 minutes, hence $p = 0.3$

The probability that <u>at most 2</u> of the next 10 callers will have to wait more than 8 minutes is:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.0282$

$P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.1211$

$P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.2335$

Then:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0282 + 0.1211 + 0.2335 = 0.3828$

0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

A similar problem is given at brainly.com/question/25537909

3 0

3 years ago

Let x = 6. Evaluate 5x + 18x.

zimovet [89]

Use the substitution method

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5(6)+18(6)

30+18(6)

Mutiply first then add

30+108

= 138

Answer: 138

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3 years ago

An organic farmer wanted to find out how many eggs a typical hen lays during 1 month. She chose 8 hens at random from the 60 hen

Marat540 [252]

First, you add them all together, and divide them by the number of quantities there are, so:
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4 years ago

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