Answer: The length is 13 inches and the width is 11 inches.
Step-by-step explanation:
Let L represent the length of the rectangle.
Let W represent the width of the rectangle.
The formula for determining the area of a rectangle is expressed as
Area = LW
The area of the rectangle is 143 square inches. This means that
LW = 143 - - - - - - - - - - - - --1
The rectangle's length is 2 in more than its width. This means that
L = W + 2
Substituting L = W + 2 into equation 1, it becomes
W(W + 2) = 143
W² + 2W - 143 = 0
W² + 13W - 11W - 143 = 0
W(W + 13) - 11(W + 13) = 0
W + 13 = 0 or W - 11 = 0
W = - 13 or W = 11
Since the width cannot be negative, it means that W = 11
L = W + 2 = 11 + 2
L = 13
A) 2x +3
Plug in the x
2(4.1) + 3
8.2+ 3= 11.2
A is 11.2
B) 16-5y
Plug in the y
16 - 5(2.3)
16- 11.5= 4.5
B is 4.5
C) x+y
Plug in x and y
4.1 + 2.3= 6.4
C is 6.4
If we firstly consider only the terms in x.
subtract 2x from both sides of the equation
⇒5+2x
−2x=2x−2x
+6
Observe that the x terms are eliminated and we are left with
5+0=0+6 that is 5=6 which is invalid
There is no solution to this equation.
Answer:
There are 8 males in the class and 42 females.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
x is the number of females.
y is the number of males.
Class of 50 students
This means that 
The number of females is 2 more than 5 times the number of males.
This means that 
So, finding y, the number of males:
Females:
There are 8 males in the class and 42 females.
