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pishuonlain [190]
4 years ago
15

A $20,000 car decreases in value by 15% each year how much is the car worth after three years

Mathematics
2 answers:
storchak [24]4 years ago
7 0

Answer: It is worth $11,000 after 3 years

Step-by-step explanation:

rjkz [21]4 years ago
7 0

Answer:

16,000

Step-by-step explanation:

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A researcher is comparing the effectiveness of three devices designed to help people who snore. There are 210 people who snore p
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Answer:

the answer is 000-210

Step-by-step explanation:

edge 2021

8 0
3 years ago
The vertices of figure EFGH have coordinates E(1, 3), F(2, 5), G(4, 4) , and H(3, 3) . The vertices of figure E'F'G'H' have coor
ad-work [718]
The correct answer is A) a translation 2 units right and 4 units down.

Both of the reflections listed would keep the digits but change their signs and/or placement.
A translation 2 units right subtracts 2 from the x-coordinate.  A translation 4 units down subtracts 4 from the y-coordinate.  Comparing each pre-image point to its image, we can see that is what happened.
7 0
3 years ago
566x6388 i need help
uranmaximum [27]

3615608 there you go!!

3 0
3 years ago
Read 2 more answers
What is the probability that all the roots of x2 + bx + c = 0 are real? [0,1]?
notsponge [240]

x^2+bx+c will have real roots when the discriminant of the quadratic, \Delta=b^2-4c, is non-negative, i.e.

b^2-4c\ge0\implies b^2\ge4c

Your question about probability is currently impossible to answer without knowing exactly what the experiment is. Are you picking b,c at random from some interval? Is the choice of either distributed a certain way?

I'll assume the inclusion of "[0,1]" in your question is a suggestion that both b,c are chosen indepently of one another from [0, 1]. Let B,C denote the random variables that take on the values of b,c, respectively. I'll assume B,C are identical and follow the standard uniform distribution, i.e. they each have the same PDF and CDF as below:

f_X(x)=\begin{cases}1&\text{for }0

F_X(x)=\begin{cases}0&\text{for }x

where X is either of B,C.

Then the question is to find P(B^2\ge4C). We have

P(B^2\ge4C)=P\left(C\le\dfrac{B^2}4\right)

and we can condition the random variable C on the event of B=b by supposing

P\left(C\le\dfrac{B^2}4\right)=P\left(\left(C\le\dfrac{B^2}4\right)\land(B=b)\right)=P\left(C\le\dfrac{B^2}4\mid B=b\right)\cdot P(B=b)

then integrate over all possible values of b.

=\displaystyle\int_{-\infty}^\infty P\left(C\le\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_{-\infty}^\infty F_C\left(\dfrac{b^2}4\right)f_B(b)\,\mathrm db

=\displaystyle\int_0^1\dfrac{b^2}4\,\mathrm db=\frac1{12}

4 0
3 years ago
Tasha gets $7.50 every week for walking the neighbors dog daily she also makes and sells bracelets for $2.50 each she wants to e
mrs_skeptik [129]
25-7.50= 17.50
17.50/2.50= 7
 she needs to make at least 7 bracelets and sell them
7 0
3 years ago
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