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skelet666 [1.2K]
3 years ago
5

. Evaluate.14.15 ÷ 5

Mathematics
2 answers:
Stolb23 [73]3 years ago
8 0
2.83 is your answer. It actually isn't hard. Look up some YouTube videos or go to Khan Academy. It helps a lot if you actually care enough to pay attention. Anyway, I used a calculator.
jek_recluse [69]3 years ago
4 0
Use calculator 14.15 didvided by 5 is 2.83
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What’s the end behavior?
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The answer is C, as x goes to negative infinity and positive infinity, g(x) goes to negative infinity.

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3 years ago
400 grams = 480 ml<br> so,<br> 180 grams = ?
Viefleur [7K]

Answer: 216 ml

Step-by-step explanation:

400 grams = 480 ml

180 grams = ?

Since the value of 180 grams in milliliters is unknown, let the unknown be Z

Thus, 400 grams = 480 ml

180 grams = Z

To get the value of Z, cross multiply

Then, Z x 400 grams = 480ml x 180 grams

400Z = 86400

Divide both sides by 400

400Z/400 = 86400/400

Z = 216

Thus, 180 grams is equal to 216 milliliters.

5 0
3 years ago
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A ladder 15 feet long leans against the top of a structure at a 60 degree angle to the ground. What is the height of the buildin
Goshia [24]

Answer:

height of the building is 12.99 feet.

Step-by-step explanation:

given, try to analyse:

  • ladder 15 feet long.
  • 60 degree angle to the ground.

the height of the building is opposite to the angle 60° and given hypotenuse, the ladder of 15 feet long.

using sine rule:

sin(x) = \frac{opposite}{hypotenuse}

sin(60) = \frac{opposite}{15}

opposite = sin(60) *15

opposite = 12.99feet

Therefore the height of the building is 12.99 feet.

7 0
2 years ago
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Simplify the expression. tan(sin^−1 x)
Blizzard [7]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2799412

_______________


Let  \mathsf{\theta=sin^{-1}(x)\qquad\qquad-\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2}.}

(that is the range of the inverse sine function).


So,

\mathsf{sin\,\theta=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\theta=x\qquad\quad(i)}


Square both sides:

\mathsf{sin^2\,\theta=x^2\qquad\qquad(but~sin^2\,\theta=1-cos^2\,\theta)}\\\\ \mathsf{1-cos^2\,\theta=x^2}\\\\ \mathsf{1-x^2=cos^2\,\theta}\\\\ \mathsf{cos^2\,\theta=1-x^2}


Since \mathsf{-\,\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2},} then \mathsf{cos\,\theta} is positive. So take the positive square root and you get

\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\quad(ii)}


Then,

\mathsf{tan\,\theta=\dfrac{sin\,\theta}{cos\,\theta}}\\\\\\ \mathsf{tan\,\theta=\dfrac{x}{\sqrt{1-x^2}}}\\\\\\\\ \therefore~~\mathsf{tan\!\left[sin^{-1}(x)\right]=\dfrac{x}{\sqrt{1-x^2}}\qquad\qquad -1\ \textless \ x\ \textless \ 1.}


I hope this helps. =)


Tags:  <em>inverse trigonometric function sin tan arcsin trigonometry</em>

3 0
3 years ago
Read 2 more answers
Please help !!!!!!!!!!!
Dvinal [7]

Answer: 6) x= 17 Same side interior angles sum to 180.

7) x= 3 Alternate exterior angles are equal.

8) x= 35 Corresponding angles are equal.

9) x= 12 Alternate interior angles are equal

Step-by-step explanation:

6) x= Same side interior angles sum to 180.

53+(8x-9)= 180

44+8x= 180

Subtract 44 from both sides

8x= 136

Divide both sides by 8

X = 17

7) x= Alternate exterior angles are equal. 15x+29= 26x-4

Subtract 15x from both sides

29= 11x-4

Add 4 to both sides

33= 11x

Divide both sides by 11

X=3

8) x= Corresponding angles are equal.

4x+7= 6x-63

Subtract 4x from both sides

7 = 2x -63

Add 63 to both sides

70= 2x

Divide both sides by 2

X= 35

9) x= Alternate interior angles are equal

9x+37= 14x-23

Subtract 9 x from both sides

37= 5x -23

Add 23 to both sides

60= 5x

Divide both sides by 5

12=x

7 0
2 years ago
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