(2,3) I think. I'm not in Algebra 1, so yeah
Answer:
n = -5
Step-by-step explanation:
Solve for n:
n + 2 = 4 n + 17
Hint: | Move terms with n to the left hand side.
Subtract 4 n from both sides:
(n - 4 n) + 2 = (4 n - 4 n) + 17
Hint: | Combine like terms in n - 4 n.
n - 4 n = -3 n:
-3 n + 2 = (4 n - 4 n) + 17
Hint: | Look for the difference of two identical terms.
4 n - 4 n = 0:
2 - 3 n = 17
Hint: | Isolate terms with n to the left hand side.
Subtract 2 from both sides:
(2 - 2) - 3 n = 17 - 2
Hint: | Look for the difference of two identical terms.
2 - 2 = 0:
-3 n = 17 - 2
Hint: | Evaluate 17 - 2.
17 - 2 = 15:
-3 n = 15
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of -3 n = 15 by -3:
(-3 n)/(-3) = 15/(-3)
Hint: | Any nonzero number divided by itself is one.
(-3)/(-3) = 1:
n = 15/(-3)
Hint: | Reduce 15/(-3) to lowest terms. Start by finding the GCD of 15 and -3.
The gcd of 15 and -3 is 3, so 15/(-3) = (3×5)/(3 (-1)) = 3/3×5/(-1) = 5/(-1):
n = 5/(-1)
Hint: | Simplify the sign of 5/(-1).
Multiply numerator and denominator of 5/(-1) by -1:
Answer: n = -5
Good evening ,
Answer:
In this case the dilation is a reduction (as you can see the image triangle is smaller than the original triangle)
and also the scale factor = OA’/OA = 2/6 = 1/3
since -1 < 1/3 < 1 then it’s a reduction.
Step-by-step explanation:
Look at the photo below for more details (notice OA’ and OA).
________________________________________________
:)
1 billion dollars × 6 inches per dollar = 6 billion inches / 63,360 inches per mile = 94,636.97 miles coverted by1 billion bills. answer = 94,636.97 miles
Answer:
Part A: 13.2
Part B: see below
Step-by-step explanation:
<u>Part A</u>:
13.245 rounded to tenths is 13.2
<u>Part B</u>:
The rule is ...
<em>Add 1 in the number place you're rounding to if the digit to its right is 5 or more. Drop (or zero) all digits to the right of the place you're rounding to.</em>
Here, the digit to the right of the tenths place is 4, so no action is taken other than dropping digits to the right of the tenths place.