Answer:
74cm
Step-by-step explanation:
length (l) = 28cm
breadth(b) = 9cm
Perimeter = 2(l + b)
= 2(28 + 9)
= 2 x 37
= 74cm
Answer:
Step-by-step explanation:
Remark
Triangle BAC is isosceles. It has 2 sides that are both radii of the circle. I assume that C is the center of the circle.
Givens
AC = BC Both of these are radii.
<BCD = 20o Given
<A and <B are equal Both are opposite a radii of the circle
C is the circle's center Assumed otherwise we can't do it.
Solution
<BCD is an exterior angle of Triangle ACB It's on the same straight line as D and A
The sum of 2 remote interior angles = the sum of the exterior angle.
BAC = ABC Stated above
BAC + ABC = 20 Stated right above.
2BAD = 20
BAD = 20/2
BAD = 10
Add 1/9 to both sides
n^2+2/3n+1/9=0
factor
I recognize a perfect square binomial
(a+b)^2=a^2+2ab+b^2
1n^2+2(n)(1/3)+(1/3)^2
(n+1/3)^2=0
set to zero
n+1/3=0
minus 1/3
n=-1/3
The answer is B. (2x + 5)(x + 1)You could answer this by expanding each answer until you found one that matched 2x^2 + 7x + 5, but I will only show how the answer expands:
2x × x = 2x^2
5 × x = 5x
2x × 1 = 2x
5 × 1 = 5
So in total those brackets expand to 2x^2 + 7x + 5. I hope this helps!
Answer:
Step-by-step explanation:
(2x^2-x)+(x^2+3x-1)
2x^2-x+x^2+3x-1
x^2+3x-1
5x^2+2x-1+(4x^2-x+2)
5x^2+2x-1+4x^2+x-2
9x^2+6x-3
(3x^2+2x+1)+(x^2-1)
3x^2+2x+1+x^2-1
4x^2+2x
-x^2-1+(4x^2-x)
-x^2-1+4x^2-x
3x^2-1-x