24.
This is because if we double the base and the height in the area equation it will raise any number by a factor of 4.
To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band

[recall



or 20(x+5) if you wish.
325 - [4(58 - 19) + (75 / 3)]
Divide:
325 - [4(58 - 19) + 25]
Distribute 4:
325 - [232 - 76 + 25]
Subtract:
325 - [156 + 25]
Add:
325 - [181]
Subtract:
144
No.
Tom forgot about the area of the top/roof, the floor and roof are different dimensions/areas, making his method incomplete.
He needs to find area of Roof, Floor then times height.