We have to see how many times 130 fits into 1494.23:
So now we have to multiply this by the amount of time needed for 130 meters:
11.4940*1=11.4940.
So the answer is 11.4940 minutes.
Let D be dogs and C be cats
<em>dogs, d, is initially five less than twice the number of cats, c</em>
D + 5 = 2C
<em>If she decides to add three more of each, the ratio of cats to dogs will be</em>
D + 8 = 2C + 3
<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>
Simply plug in the numbers
20 + 5 = 2(15)
This is clearly not true: 25 does not equal 30
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Step-by-step explanation:
Average between these no.s =
approx
Answer:
min = a_1
for i:= 2 to n:
if 
< min then min =
return min
Step-by-step explanation:
We call the algorithm "minimum" and a list of natural numbers 
So lets first set the minimum to 
min = a_1
now we want to check all the other numbers.
We can use a simple for loop, to find the minimum
min = a_1
for i:= 2 to n:
if < min then min =
return min
