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givi [52]
3 years ago
14

Find the slope of the line that passes through (2, 5) and (6,4).

Mathematics
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

The slope of the line is \frac{1}{-4}.

Step-by-step explanation:

We use the formula change in y over change in x to find the slope:

\frac{5-4}{2-6}

Then we simplify:

\frac{1}{-4}

The slope of the line is \frac{1}{-4}.

You might be interested in
What is square root of 167?
enot [183]
The square root of 167 would be 12.922847. If you need it rounded to the nearest tenth it would be 12.9

If you need t rounded to the nearest hundredth, it would be 12.92.


Hope this helps :)
7 0
3 years ago
A glider flies 13 miles north from the airport and then 24 miles diagonally southeast. Approximately how far west does the glide
NISA [10]

Answer:

20.2 miles

Step-by-step explanation:

This can be described by the three sides of a right angled triangle. Let the distance of the glider to the airport be represented by x, applying the Pythagoras theorem:

/hyp/^{2} = /adj1/^{2} + /adj2/^{2}

/24/^{2} = /x/^{2} + /13/^{2}

576 = x^{2} + 169

x^{2} = 576 - 169

   = 407

x = \sqrt{407}

  = 20.1742

x = 20.2 miles

The glider has to fly 20.2 miles to return to the airport.

8 0
3 years ago
(sorry bout the other one I forgot to put the picture and it wouldn't let me delete)
Sergio039 [100]
I’m pretty sure it is.
8 0
3 years ago
Read 2 more answers
Help please!! 15 points!!
maxonik [38]

Answer:

A and D

Step-by-step explanation:

One side-base right triangle and one angle-based right triangle.

6 0
3 years ago
Read 2 more answers
The initial price of buzz stock is $20 per share. After 20 days the stock price is $30 per share and after 40 days the price is
Temka [501]

Answer:

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

Step-by-step explanation:

given,

initial price of buzz stock = $ 20 per share

after 20 days

stock price = $30 per share

after 40 days

the price =  $35 per share

let say it is modeled by

y = ax² + b x + c

x = number of days

y = stock price

x = 0 y = 20

20 = a x 0 + b x 0 + c

c = 20

x = 20 y = 30

30 = 20² a + 20 b + 20

400 a + 20 b = 10...........(1)

x = 40 y = 35

35 = 40² a + 40 b + 20

1600 a + 40 b = 15...........(2)

solving equation (1)and (2)

a = - 1/160

b = 5/8

y = -\dfrac{x^2}{160}+\dfrac{5}{8}x+20

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

hence , the above equation is multipart function

5 0
3 years ago
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