Answer:
(fg)(x) = 12x^3 + 9x^2 + 28x + 21
Third option
Step-by-step explanation:
(fg)(x) = (3x^2 + 7)(4x + 3)
(fg)(x) = = (3x^2)(4x) + (3x^2)(3) + (7)(4x) + (7)(3)
(fg)(x) = 12x^3 + 9x^2 + 28x + 21
Answer:
(7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance.
Step-by-step explanation:
We have a large sample size n = 56 research cotton samples. Besides,
and
. A 95% large-sample CI for the true average percentage elongation is given by
, i.e.,
or equivalently (7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance because we have a large sample.
4(7x−3)−6=6−4(3x−7)
Distributive property
28x - 12 - 6 = 6 - 12x + 28
28x - 18 = -12x + 34
28x + 12x = 34 + 18
40x = 52
x = 52/40
x = 13/10
or
x = 1 3/10 (mixed number: 1 and 3/10)
Answer:
256x * 16
Step-by-step explanation:
(4x * 4x * 4) * (4x * 4x * 4 )
(16x * 4 ) * ( 16x *4)
16x * 16x = 256x
4 * 4 = 16
256x * 16
hope this helped a little
* = multiply
12x²-8x-15 should be your answer