If cos a<0 and cot a is undefined then where does the terminal side of a located?

Suppose that a disk drive has 5,000 cylinders, numbered 0 to 4,999. the drive is currently serving a request at cylinder 2,150,

Anni [7]

Answer:

13011, 7586, 7492 , 7424, 9917, and 9137.

Step-by-step explanation:

(1). FCFS is generally based on what is refer to as first come, first serve. That is to say the first one to come will be treated first so, we have that;

FCFS = 81 + 857 + 1084 + 504 + 2256 + 1074 + 1262 + 1167 + 3442 + 1284 = 13011.

(2). (SSTF) Is all about the shortest distance, for example in this question the shortest distance is =

Thus;

Total distance = (2150 - 2069) + (2296 - 2069) + ( 2296 - 2800) +( 3681 - 2800) + (4965 - 3681) + ( 4965 - 1618) + ( 1618-1523) + ( 1523-1212) + ( 1212-544) + ( 544 - 356).

=81 + 227 + 504 + 881 + 1284 + 3347 + 95 + 311 + 668 + 188 = 7586.

(3).SCAN deals with the processing of the nearest request

The distance =146 + 504 +881 + 1284 + 34(4999-4965) + 2930(4999-2069) + 451 + 95 + 311 + 668 +188 = 7492.

(4). LOOK is just like scan.

The distance = 146 + 504 + 881 + 1284 + 2896 + 451 + 95 + 311 + 668 + 188 = 7424.

(5). C-SCAN: this is the kind of scan from one end to the other.

The distance = 146 + 504 +881 +1284 + 34 (4999 - 4965) + 4999 (4999 -0 )+ 356 (356 -0 )+ 188 + 668 + 311 + 95 + 451 = 9917.

(6). C-LOOK : moves in the following order: 2150, 2296, 2800, 3681, 4965, here head moves back 356, 544, 1212, 1523, 1618, 2069.

Thus;

The distance = 146 + 504 + 881+ 1284 + 4609 (4965 - 356) + 188 + 668 + 311+ 95 + 451 = 9137.

4 0

3 years ago

How many times do parallel lines intersect?

yanalaym [24]

Answer:

A) 0

Step-by-step explanation:

The actual definition of parallel lines are lines that never intersect, so the answer is 0

5 0

3 years ago

4/9=w+4 solve for w.

Elina [12.6K]

Answer:

-32/9

Step-by-step explanation:

4/9=w+4

4/9-4/1=w

4-36/9=w

w=-32/9 or w=-3.56

5 0

3 years ago

Read 2 more answers

The length of a rectangle is 2 foot less than 3 times its width. Find the the dimensions of this rectangle if the area is 96 squ

Xelga [282]

For example,area = a, length = l, width = w
First we write two equations. The easier equation is the area equation, which we know to be
a = l x w
So that the first equation is :
96 = l x w 

we make the second equation of the following statements :
The length of a rectangle is 2 foot less than 3 times its width.
so it becomes :
l = 3w - 2

To solve, we can use the substitution method.

$96 = l \times w\\96=(3w-2) \times w\\96=3w^{2}-2w\\3w^{2}-2w-96=0~~~~~~[now\ factor\ the\ equation]\\ (3w+16)(w-6)=0$

$3w+16=0\\3w=-16\\w= -\frac{16}{3}~~~~\Rightarrow~~~answer\ doesnt\ make\ sense\ , negative\ width.
$

$w-6=0\\\boxed{w=6~~~~~~~\Rightarrow~~~~positive\ answer\ for\ width\ makes\ sense }
$

So if our width is 6, Now substitute the value of w = 6 into equation 2 

$l=3w-2\\l=3(6)-2\\l=18-2\\l=16$

So "w" = 6 and "l" = 16, and if we multiply them together, we get the correct area, 96. So our dimensions are 6 by 16.

6 0

3 years ago

Find the derivative using the limit process of f (x) = - 10x

zubka84 [21]

Answer:

$\frac{d}{dx} f(x) =-10$