Question

what is the slope of a line perpendicular to the line whose equation is 5x+6y=42. fully reduce your answer​

Answer 1

Answer:

the slope of the line that is perpendicular to the given line is  $\frac{6}{5}$

Step-by-step explanation:

As the slope intercept form is

$y=mx+b$

Where

• m is the slope
• b is the y-intercept

Considering the equation

$5x+6y=42$

$\mathrm{Slope-Intercept\:form\:of}\:5x+6y=42:\quad y=-\frac{5}{6}x+7$

$\mathrm{Slope\:of\:}-\frac{5}{6}x+7:\quad m=-\frac{5}{6}$

As we know that perpendicular lines have negative reciprocal slopes.

So,

$-\frac{1}{-\frac{5}{6}}=\frac{6}{5}$

Hence, the slope of the line that is perpendicular to the given line is $\frac{6}{5}$

Keywords: slope, slope of a line, equation

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