F(1) = -f(0) +5 = -3 +5 = 2
f(2) = -f(1) +5 = -2 +5 = 3
f(2) = 3
_____
The sequence appears to alternate between 3 and 2.
Answer:
Step-by-step explanation:
<u>Given:</u>
and
<u>Find g(f(x)), substitute the value of f(x) into equation:</u>
- g(f(x)) = g(2x + 1) = (2x + 1) - 3 = 2x - 2
Answer:
Step-by-step explanation:
Let the rate at which the bacteria grow be represented by the exponential equation
P(t) = P0e^kt
P(t) is the population of the bacteria after time t
P0 is the initial population
k is the constant of variation
t is the time
If the initial Population is 160 bacteria's, them the equation becomes;
P(t) = 160e^kt
b) if After 5 hours there will be 800 bacteria, this means
at t = 5 p(t) = 800
Substitute and get k
800 = 160e^5k
800/160 = e^5k
5 = e^5k
Apply ln to both sides
Ln5 = lne^5k
ln5 = 5k
k = ln5/5
k = 0.3219
Next is to calculate the population after 7hrs i.e at t = 7
P(7) = 160e^0.3219(7)
P(7) = 160e^2.2532
P(7) = 160(9.5181)
P(7) = 1522.9
Hence the population after 7houra will be approximately 1523populations
c) To calculate the time it will take the population to reach 2790
When p(t) = 2790, t = ?
2790 = 160e^0.3219t
2790/160 = e^0.3219t
17.4375 = e^0.3219t
ln17.4375 = lne^0.3219t
2.8587 = 0.3219t
t = 2.8587/0.3219
t = 8.88 hrs
Hence it will take approximately 9hrs for the population to reach 2790
Answer:
y=2/5x+4.8
Step-by-step explanation:
Proof
Answer:
The proportion of people who were caught after being on the 1010 Most Wanted list would be 40.81%.
Step-by-step explanation:
Since the FBI wants to determine the effectiveness of their 1010 Most Wanted list, and to do so, they need to find out the fraction of people who appear on the list that are actually caught, supposing a sample of 517517 suspected criminals is drawn, and of these people, 211211 were captured, to estimate the proportion of people who were caught after being on the 1010 Most Wanted list using this data, the following calculation must be performed:
517,517 = 100
211,211 = X
211,211 x 100 / 517,517 = X
21,121,100 / 517,517 = X
40.81 = X
Therefore, the proportion of people who were caught after being on the 1010 Most Wanted list would be 40.81%.