Question

Find the equation for the line that is parallel to the line with the equation y=−14x−1y=−14x−1 passing through the point (2,0)(2,0).

Answer 1

Use formula: y-y1/x-x1=m(gradient)
so, y=-14x-1
m=-14
y-0/x-2=14/1
y=-14x+28