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3 years ago

11

Find the equation for the line that is parallel to the line with the equation y=−14x−1y=−14x−1 passing through the point (2,0)(2

,0).

1 answer:

bezimeni [28]3 years ago

7 0

Use formula: y-y1/x-x1=m(gradient)
so, y=-14x-1
m=-14
y-0/x-2=14/1
y=-14x+28

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Find the inverse of g(x) = 3x^2 - 5

Arte-miy333 [17]

Answer:

$\boxed{\sf \ \ \ g^{-1}(x)=\sqrt{\dfrac{x+5}{3}} \ \ \ }$

Step-by-step explanation:

Hello,

$x=(gog^{-1})(x)=g(g^{-1}(x))=3(g^{-1}(x))^2-5\\\\3(g^{-1}(x))^2 = x+5\\\\\\ (g^{-1}(x))^2=\dfrac{x+5}{3}\\g^{-1}(x)=\sqrt{\dfrac{x+5}{3}}$

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